转自: Android中RelativeLayout和LinearLayout性能分析
RelativeLayout的onMeasure()方法
1 | View[] views = mSortedHorizontalChildren; |
RelativeLayout 会对子View进行两次measure,因为Relative中的子View的布局是依赖于子View的相互关系,这个顺序可能与layout文件中的子View编写不一致,故在确定子View位置时,先要给子View排一下序。
又因为RelativeLayout允许A,B 2个子View,横向上B依赖A,纵向上A依赖B。所以需要横向纵向分别进行一次排序测量。
LinearLayout的onMeasure()方法
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进入measureVertical中1
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60for (int i = 0; i < count; ++i) {
final View child = getVirtualChildAt(i);
if (child == null) {
mTotalLength += measureNullChild(i);
continue;
}
if (child.getVisibility() == View.GONE) {
i += getChildrenSkipCount(child, i);
continue;
}
if (hasDividerBeforeChildAt(i)) {
mTotalLength += mDividerHeight;
}
LinearLayout.LayoutParams lp = (LinearLayout.LayoutParams) child.getLayoutParams();
totalWeight += lp.weight;
if (heightMode == MeasureSpec.EXACTLY && lp.height == 0 && lp.weight > 0) {
// Optimization: don't bother measuring children who are going to use
// leftover space. These views will get measured again down below if
// there is any leftover space.
final int totalLength = mTotalLength;
mTotalLength = Math.max(totalLength, totalLength + lp.topMargin + lp.bottomMargin);
} else {
int oldHeight = Integer.MIN_VALUE;
if (lp.height == 0 && lp.weight > 0) {
// heightMode is either UNSPECIFIED or AT_MOST, and this
// child wanted to stretch to fill available space.
// Translate that to WRAP_CONTENT so that it does not end up
// with a height of 0
oldHeight = 0;
lp.height = LayoutParams.WRAP_CONTENT;
}
// Determine how big this child would like to be. If this or
// previous children have given a weight, then we allow it to
// use all available space (and we will shrink things later
// if needed).
measureChildBeforeLayout(
child, i, widthMeasureSpec, 0, heightMeasureSpec,
totalWeight == 0 ? mTotalLength : 0);// Measure child
if (oldHeight != Integer.MIN_VALUE) {
lp.height = oldHeight;
}
final int childHeight = child.getMeasuredHeight();
final int totalLength = mTotalLength;
mTotalLength = Math.max(totalLength, totalLength + childHeight + lp.topMargin +
lp.bottomMargin + getNextLocationOffset(child));
if (useLargestChild) {
largestChildHeight = Math.max(childHeight, largestChildHeight);
}
}
父视图在对子视图进行measure操作的过程中,使用变量mTotalLength保存已经measure过的child所占用的高度,该变量刚开始时是0。在for循环中调用measureChildBeforeLayout()对每一个child进行测量; 每次for循环对child测量完毕后,调用child.getMeasuredHeight()获取该子视图最终的高度,并将这个高度添加到mTotalLength中。在本步骤中,暂时避开了lp.weight>0的子视图,即暂时先不测量这些子视图,因为后面将把父视图剩余的高度按照weight值的大小平均分配给相应的子视图。
源码中使用了一个局部变量totalWeight累计所有子视图的weight值。处理lp.weight>0的情况需要注意,如果变量heightMode是EXACTLY
,那么,当其他子视图占满父视图的高度后,weight>0的子视图分配不到布局空间
,从而不被显示,只有当heightMode是AT_MOST或者UNSPECIFIED时,weight>0的视图才能优先获得布局高度。最后我们的结论是:如果不使用weight属性
,LinearLayout会在当前方向上进行一次measure
的过程,如果使用weight属性
,LinearLayout会避开设置过weight属性的view做第一次measure,完了再对设置过weight属性的view做第二次measure
。由此可见,weight属性对性能是有影响的,而且本身有大坑,请注意避让。
结论
- RelativeLayout慢于LinearLayout是因为它会让子View调用2次measure过程,而后者只需一次,但是有weight属性存在时,后者同样会进行两次measure。
- 无嵌套布局的情况使用LinearLayout,否则使用RelativeLayout
- DecorView的层级深度已知且固定的,上面一个标题栏,下面一个内容栏,采用RelativeLayout并不会降低层级深度,因此这种情况下使用LinearLayout效率更高。而为开发者默认新建RelativeLayout是希望开发者能采用尽量少的View层级,很多效果是需要多层LinearLayout的嵌套,这必然不如一层的RelativeLayout性能更好。因此我们应该尽量减少布局嵌套,减少层级结构。