Climbing a stair

Problem description

You are climbing a stair case. It takes n steps to reach to the top.Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?Note: Given n will be a positive integer.

Examples

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Example 1:
Input: 2
Output: 2
Explanation: There are two ways to climb to the top.
1. 1 step + 1 step
2. 2 steps
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Example 2:
Input: 3
Output: 3
Explanation: There are three ways to climb to the top.
1. 1 step + 1 step + 1 step
2. 1 step + 2 steps
3. 2 steps + 1 step

Solution

  剑指Offer上的青蛙跳台阶翻版,即斐波那契数列。

Code

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 class Solution {
public int climbStairs(int n) {
int[] res = new int[]{0, 1, 2};
if (n < 3) {
return res[n];
}
int fibMinTwo = 1,fibMinOne = 2;
int fibN = 0;
for (int i = 2; i < n; i++) {
fibN = fibMinOne + fibMinTwo;
fibMinTwo = fibMinOne;
fibMinOne = fibN;
}
return fibN;
}
}
文章目录
  1. 1. Problem description
    1. 1.1. You are climbing a stair case. It takes n steps to reach to the top.Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?Note: Given n will be a positive integer.
  2. 2. Examples
  3. 3. Solution
  4. 4. Code
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